我的思路是先找到所求数字n 所在第m圈对角线的元素为m^2-m+1，然后根据坐标差值求出n的坐标，注意奇偶坐标的处理。

/* * uva10161.cpp * *  Created on: 2013-4-16 *      Author: kevinjiang */#include
     
      #include
      
       int main() {//	setbuf(stdout,NULL);	int n;	while (scanf("%d", &n) != EOF) {		if (n == 0)		break;		int m = (int) sqrt(n - 1) + 1;		int diag = m * m - m + 1;		int diff = n - diag;		int x = m, y = m;		if (diff >= 0)		x = m - diff;		else		y = m + diff;		if(m%2==1)		printf("%d %d\n",x,y);		else		printf("%d %d\n",y,x);	}	return 0;}